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Micro-hydro systems use the motion of flowing water to generate electricity for a home, farm, school, or small village. They are renewable because the water cycle continually refills streams and rivers. Unlike solar and wind power, a stream can often provide steady energy day and night if the flow is reliable.

This makes micro-hydro especially valuable in mountainous or rural areas with nearby flowing water.

Key Facts

  • Hydropower input power is P = ρgQh, where ρ is water density, g is gravitational field strength, Q is flow rate, and h is head.
  • Useful electrical power is Pout = ηρgQh, where η is the overall efficiency of the turbine and generator.
  • Head is the vertical drop of the water, and more head usually means more available energy per liter of water.
  • Flow rate Q is the volume of water passing each second, usually measured in m^3/s or L/s.
  • A turbine converts moving water into rotation, and a generator converts that rotation into electrical energy.
  • Micro-hydro systems are often less than 100 kW and can power homes, workshops, or small communities.

Vocabulary

Micro-hydro
A small-scale hydropower system that uses flowing water to generate electricity for local use.
Head
The vertical height difference between the water intake and the turbine.
Flow rate
The volume of water that moves through a pipe or channel each second.
Turbine
A rotating machine that extracts energy from moving water.
Generator
A device that converts mechanical rotation into electrical energy using electromagnetic induction.

Common Mistakes to Avoid

  • Using stream speed alone to estimate power, which is wrong because micro-hydro power depends mainly on flow rate and vertical head.
  • Forgetting efficiency, which is wrong because real turbines, pipes, and generators always lose some energy to friction, turbulence, and heat.
  • Mixing liters per second with cubic meters per second, which is wrong because 1 m^3/s equals 1000 L/s and the power calculation will be off by a factor of 1000.
  • Assuming all stream water can be diverted, which is wrong because systems must leave enough water for ecosystems, other users, and legal flow requirements.

Practice Questions

  1. 1 A micro-hydro site has a head of 12 m and a flow rate of 0.030 m^3/s. If the overall efficiency is 60 percent, calculate the electrical power output using ρ = 1000 kg/m^3 and g = 9.8 m/s^2.
  2. 2 A village needs 2.5 kW of continuous power. A stream provides 25 L/s through a turbine with 70 percent efficiency. What head is required? Use ρ = 1000 kg/m^3 and g = 9.8 m/s^2.
  3. 3 Explain why a small stream with a large vertical drop may produce more useful power than a wide slow stream with very little drop.