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Crystal Structure Types (BCC, FCC, HCP) cheat sheet - grade 11-12

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This cheat sheet covers the three most common metallic crystal structure types: body-centered cubic, face-centered cubic, and hexagonal close-packed. Students need these structures to connect atomic arrangement with density, packing efficiency, coordination number, and material properties. A clear reference helps compare the diagrams, formulas, and key values that often appear in chemistry and materials science problems. The core ideas are unit cells, atoms per unit cell, coordination number, atomic radius relationships, and atomic packing factor. For cubic structures, the edge length aa connects to atomic radius rr through geometry, while HCP uses a hexagonal cell with an ideal ratio ca=1.633\frac{c}{a} = 1.633. Density problems use ρ=nMNAVcell\rho = \frac{nM}{N_A V_{cell}}, where nn is atoms per unit cell and VcellV_{cell} is the unit cell volume. Comparing BCC, FCC, and HCP shows why FCC and HCP are more closely packed than BCC.

Key Facts

  • In a body-centered cubic unit cell, the number of atoms per unit cell is n=2n = 2 because 88 corner atoms contribute 11 atom total and the body-center atom contributes 11 atom.
  • In a face-centered cubic unit cell, the number of atoms per unit cell is n=4n = 4 because 88 corners contribute 11 atom total and 66 face atoms contribute 33 atoms total.
  • For BCC, atoms touch along the body diagonal, so 4r=3a4r = \sqrt{3}a and a=4r3a = \frac{4r}{\sqrt{3}}.
  • For FCC, atoms touch along the face diagonal, so 4r=2a4r = \sqrt{2}a and a=22ra = 2\sqrt{2}r.
  • The atomic packing factor is APF=volume of atoms in unit cellvolume of unit cellAPF = \frac{\text{volume of atoms in unit cell}}{\text{volume of unit cell}}.
  • BCC has coordination number 88 and atomic packing factor APF0.68APF \approx 0.68.
  • FCC and HCP both have coordination number 1212 and atomic packing factor APF0.74APF \approx 0.74.
  • Crystal density is calculated with ρ=nMNAVcell\rho = \frac{nM}{N_A V_{cell}}, where MM is molar mass and NA=6.022×1023 mol1N_A = 6.022 \times 10^{23}\ \text{mol}^{-1}.

Vocabulary

Unit cell
A unit cell is the smallest repeating three-dimensional block that shows the symmetry and arrangement of atoms in a crystal.
Body-centered cubic
Body-centered cubic, or BCC, is a cubic structure with atoms at the corners and one atom at the center of the cube.
Face-centered cubic
Face-centered cubic, or FCC, is a cubic structure with atoms at the corners and at the centers of all six faces.
Hexagonal close-packed
Hexagonal close-packed, or HCP, is a close-packed structure with layers arranged in an ABABABAB repeating pattern.
Coordination number
Coordination number is the number of nearest neighboring atoms touching a given atom in a crystal structure.
Atomic packing factor
Atomic packing factor is the fraction of a unit cell's volume occupied by atoms, given by APF=VatomsVcellAPF = \frac{V_{atoms}}{V_{cell}}.

Common Mistakes to Avoid

  • Counting corner atoms as whole atoms is wrong because each corner atom is shared by 88 unit cells, so each corner contributes only 18\frac{1}{8} atom.
  • Using the BCC radius formula for FCC is wrong because BCC atoms touch along the body diagonal, while FCC atoms touch along the face diagonal.
  • Assuming BCC is close-packed is wrong because BCC has APF0.68APF \approx 0.68, while close-packed FCC and HCP have APF0.74APF \approx 0.74.
  • Forgetting to convert radius units is wrong because density calculations require consistent units, such as converting pm\text{pm} to cm\text{cm} before finding VcellV_{cell} in cm3\text{cm}^3.
  • Using n=1n = 1 for all unit cells is wrong because BCC has n=2n = 2, FCC has n=4n = 4, and HCP depends on the specific unit cell chosen.

Practice Questions

  1. 1 A BCC metal has atomic radius r=125 pmr = 125\ \text{pm}. Calculate the unit cell edge length aa using a=4r3a = \frac{4r}{\sqrt{3}}.
  2. 2 An FCC metal has molar mass M=63.55 g mol1M = 63.55\ \text{g mol}^{-1} and edge length a=361 pma = 361\ \text{pm}. Calculate its density using ρ=nMNAa3\rho = \frac{nM}{N_A a^3} with n=4n = 4.
  3. 3 For an FCC unit cell, show how the atoms from corners and faces add to n=4n = 4 atoms per unit cell.
  4. 4 Explain why FCC and HCP have the same coordination number and packing efficiency even though their layer stacking patterns are different.