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Simple harmonic motion describes repeated back-and-forth motion caused by a restoring force that is proportional to displacement. This cheat sheet helps students recognize SHM in springs, pendulums, vibrations, and waves. It is useful because many physics problems use the same core relationships for position, velocity, acceleration, period, and energy. Grades 10-12 students need these formulas to connect graphs, equations, and physical motion.

Key Facts

  • Simple harmonic motion occurs when the restoring force is proportional to displacement and opposite in direction, so F=kxF = -kx for a spring.
  • Displacement in SHM can be modeled by x(t)=Acos(ωt+ϕ)x(t) = A\cos(\omega t + \phi) or x(t)=Asin(ωt+ϕ)x(t) = A\sin(\omega t + \phi).
  • Angular frequency is related to frequency and period by ω=2πf=2πT\omega = 2\pi f = \frac{2\pi}{T}.
  • Velocity in SHM has maximum magnitude vmax=Aωv_{\max} = A\omega and can be written as v(t)=Aωsin(ωt+ϕ)v(t) = -A\omega\sin(\omega t + \phi) for cosine displacement.
  • Acceleration in SHM is proportional to displacement and opposite in direction, so a=ω2xa = -\omega^2 x.
  • The period of a mass-spring oscillator is T=2πmkT = 2\pi\sqrt{\frac{m}{k}}.
  • For small angles, the period of a simple pendulum is T=2πLgT = 2\pi\sqrt{\frac{L}{g}}.
  • Total mechanical energy in an ideal spring oscillator is constant and equals E=12kA2E = \frac{1}{2}kA^2.

Vocabulary

Amplitude
Amplitude is the maximum displacement from equilibrium, represented by AA.
Equilibrium Position
The equilibrium position is the point where the net restoring force is zero.
Period
Period is the time for one complete cycle of motion, represented by TT.
Frequency
Frequency is the number of cycles per second and is given by f=1Tf = \frac{1}{T}.
Angular Frequency
Angular frequency measures how quickly the oscillator moves through its cycle and is given by ω=2πf\omega = 2\pi f.
Restoring Force
A restoring force is a force that acts toward equilibrium and often has the form F=kxF = -kx.

Common Mistakes to Avoid

  • Using F=kxF = kx instead of F=kxF = -kx, because the negative sign shows that the force points opposite the displacement.
  • Confusing frequency and angular frequency, because ff is measured in hertz while ω\omega is measured in radians per second and equals 2πf2\pi f.
  • Assuming acceleration is greatest at equilibrium, because acceleration is actually a=ω2xa = -\omega^2 x and is zero when x=0x = 0.
  • Using the pendulum formula for large swings, because T=2πLgT = 2\pi\sqrt{\frac{L}{g}} only works well for small angles.
  • Thinking the period of a spring depends on amplitude, because an ideal mass-spring oscillator has T=2πmkT = 2\pi\sqrt{\frac{m}{k}} and amplitude is not in the formula.

Practice Questions

  1. 1 A 0.50kg0.50\,\text{kg} mass is attached to a spring with k=200N/mk = 200\,\text{N/m}. Find the period TT of the motion.
  2. 2 An oscillator has amplitude A=0.12mA = 0.12\,\text{m} and angular frequency ω=8.0rad/s\omega = 8.0\,\text{rad/s}. Find the maximum speed vmaxv_{\max}.
  3. 3 A pendulum has length L=1.6mL = 1.6\,\text{m} on Earth where g=9.8m/s2g = 9.8\,\text{m/s}^2. Find its period using the small-angle approximation.
  4. 4 Explain why the acceleration of an object in SHM always points toward equilibrium, even when the object is moving away from equilibrium.