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This cheat sheet covers Avogadro's number and the mole concept through clear worked-example style rules. Students need it because chemistry often connects tiny particles to measurable lab amounts. The mole is the counting unit that makes this connection possible.

These relationships are used in formulas, lab calculations, and chemical equations.

The most important idea is that 1 mol1\ \text{mol} contains 6.022×10236.022 \times 10^{23} particles. Molar mass connects moles to grams, using units of g/mol\text{g/mol}. Particle conversions use particles=mol×6.022×1023\text{particles} = \text{mol} \times 6.022 \times 10^{23}, while mass conversions use mol=massmolar mass\text{mol} = \frac{\text{mass}}{\text{molar mass}}.

Many mole problems become easier when you write the given quantity, choose the correct conversion factor, and cancel units.

Key Facts

  • Avogadro's number is 6.022×10236.022 \times 10^{23}, so 1 mol1\ \text{mol} of any substance contains 6.022×10236.022 \times 10^{23} particles.
  • To convert moles to particles, use particles=mol×6.022×1023\text{particles} = \text{mol} \times 6.022 \times 10^{23}.
  • To convert particles to moles, use mol=particles6.022×1023\text{mol} = \frac{\text{particles}}{6.022 \times 10^{23}}.
  • Molar mass is the mass of 1 mol1\ \text{mol} of a substance and is measured in g/mol\text{g/mol}.
  • To convert grams to moles, use mol=mass in gmolar mass in g/mol\text{mol} = \frac{\text{mass in g}}{\text{molar mass in g/mol}}.
  • To convert moles to grams, use mass in g=mol×molar mass in g/mol\text{mass in g} = \text{mol} \times \text{molar mass in g/mol}.
  • The molar mass of a compound equals the sum of the atomic masses of all atoms in its formula, such as H2O=2(1.01)+16.00=18.02 g/molH_2O = 2(1.01) + 16.00 = 18.02\ \text{g/mol}.
  • In a balanced chemical equation, coefficients give mole ratios, such as 2H2+O22H2O2H_2 + O_2 \rightarrow 2H_2O meaning 2 mol H22\ \text{mol }H_2 reacts with 1 mol O21\ \text{mol }O_2.

Vocabulary

Mole
A mole is a counting unit equal to 6.022×10236.022 \times 10^{23} particles of a substance.
Avogadro's Number
Avogadro's number is 6.022×10236.022 \times 10^{23}, the number of particles in 1 mol1\ \text{mol}.
Molar Mass
Molar mass is the mass of 1 mol1\ \text{mol} of a substance, usually written in g/mol\text{g/mol}.
Particle
A particle is the basic unit being counted, such as an atom, molecule, ion, or formula unit.
Formula Unit
A formula unit is the simplest whole-number ratio of ions in an ionic compound, such as NaClNaCl.
Conversion Factor
A conversion factor is a ratio equal to 11 that changes units, such as 6.022×1023 particles1 mol\frac{6.022 \times 10^{23}\ \text{particles}}{1\ \text{mol}}.

Common Mistakes to Avoid

  • Multiplying when converting particles to moles is wrong because particles must be divided by 6.022×10236.022 \times 10^{23} using mol=particles6.022×1023\text{mol} = \frac{\text{particles}}{6.022 \times 10^{23}}.
  • Using atomic mass instead of molar mass for a compound is wrong because compounds require adding every atom in the formula, such as CO2=12.01+2(16.00)CO_2 = 12.01 + 2(16.00).
  • Forgetting subscripts in formulas is wrong because H2OH_2O has 22 hydrogen atoms and 11 oxygen atom, so its molar mass is not 1.01+16.001.01 + 16.00.
  • Leaving units out is wrong because units show whether the answer should be mol\text{mol}, g\text{g}, or particles and help catch incorrect conversion factors.
  • Rounding too early is wrong because small rounding errors can grow during multi-step conversions, so keep extra digits until the final answer.

Practice Questions

  1. 1 How many molecules are in 2.50 mol2.50\ \text{mol} of CO2CO_2?
  2. 2 How many moles are in 3.011×10243.011 \times 10^{24} atoms of NeNe?
  3. 3 What is the mass in grams of 0.750 mol0.750\ \text{mol} of H2OH_2O if the molar mass of H2OH_2O is 18.02 g/mol18.02\ \text{g/mol}?
  4. 4 Explain why 1 mol1\ \text{mol} of HeHe and 1 mol1\ \text{mol} of H2OH_2O contain the same number of particles but do not have the same mass.