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Titration calculations help students determine an unknown concentration by reacting a measured volume with a solution of known concentration. This cheat sheet covers the step-by-step process for acid-base titrations, including converting volumes, using molarity, and applying mole ratios. Students need these skills to solve lab problems, check experimental results, and connect balanced equations to real measurements.

Key Facts

  • Molarity is calculated with M=nVM = \frac{n}{V}, where MM is molarity, nn is moles of solute, and VV is volume in liters.
  • Rearrange molarity as n=MVn = MV to find moles when concentration and volume are known.
  • Always convert milliliters to liters using VL=VmL1000V_{L} = \frac{V_{mL}}{1000} before using molarity calculations.
  • For a balanced reaction aA+bBcC+dDaA + bB \rightarrow cC + dD, the mole ratio between AA and BB is a mol Ab mol B\frac{a\text{ mol }A}{b\text{ mol }B}.
  • At the equivalence point, the moles of acid and base have reacted in the exact ratio shown by the balanced chemical equation.
  • For a monoprotic acid and a hydroxide base reacting in a 1:11:1 ratio, MacidVacid=MbaseVbaseM_{acid}V_{acid} = M_{base}V_{base}.
  • For non-1:11:1 acid-base reactions, use MacidVacida=MbaseVbaseb\frac{M_{acid}V_{acid}}{a} = \frac{M_{base}V_{base}}{b} only when aa and bb are the balanced coefficients for acid and base.
  • Percent error in a titration result can be calculated with % error=experimentalacceptedaccepted×100%\%\text{ error} = \left|\frac{\text{experimental} - \text{accepted}}{\text{accepted}}\right| \times 100\%.

Vocabulary

Titration
A lab method that uses a solution of known concentration to find the concentration of another solution.
Titrant
The solution of known concentration that is added from a buret during a titration.
Analyte
The solution being tested, usually placed in the flask, whose concentration is unknown.
Endpoint
The point in a titration when the indicator changes color and the titration is stopped.
Equivalence Point
The point where reactants have combined in the exact mole ratio required by the balanced equation.
Molarity
A concentration unit equal to moles of solute per liter of solution, written as M=nVM = \frac{n}{V}.

Common Mistakes to Avoid

  • Using milliliters directly in M=nVM = \frac{n}{V} is wrong because molarity requires volume in liters, so 25.0 mL25.0\text{ mL} must become 0.0250 L0.0250\text{ L}.
  • Assuming every titration is 1:11:1 is wrong because the balanced equation may require a different mole ratio, such as 1 mol H2SO41\text{ mol }H_2SO_4 reacting with 2 mol NaOH2\text{ mol }NaOH.
  • Confusing endpoint with equivalence point is wrong because the endpoint is the observed color change, while the equivalence point is the exact stoichiometric point.
  • Rounding too early is wrong because small volume and concentration errors can noticeably change the final molarity, so keep extra digits until the last step.
  • Putting the unknown concentration in the wrong place is wrong because the equation must match which solution is acid, base, titrant, or analyte before solving.

Practice Questions

  1. 1 A student titrates 25.00 mL25.00\text{ mL} of HClHCl with 0.100 M NaOH0.100\text{ M }NaOH. If 18.60 mL18.60\text{ mL} of NaOHNaOH is required and the reaction is 1:11:1, what is the molarity of the HClHCl?
  2. 2 How many moles of NaOHNaOH are in 32.40 mL32.40\text{ mL} of 0.150 M NaOH0.150\text{ M }NaOH?
  3. 3 For the reaction H2SO4+2NaOHNa2SO4+2H2OH_2SO_4 + 2NaOH \rightarrow Na_2SO_4 + 2H_2O, what volume of 0.200 M NaOH0.200\text{ M }NaOH is needed to neutralize 20.00 mL20.00\text{ mL} of 0.100 M H2SO40.100\text{ M }H_2SO_4?
  4. 4 A student stops a titration after the indicator becomes dark pink instead of faint pink. Explain how this would affect the calculated concentration of the unknown acid.