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Ideal Gas Law Calculator

Solve PV = nRT for any variable. Choose your units for pressure, volume, and temperature, and see the step-by-step calculation with all unit conversions.

Gas Container

P=1.00 atm, V=22.4 L

Parameters

mol

Results

Pressure
1.000 atm
Pressure (P)
1.000 atm
Volume (V)
22.41 L
Moles (n)
1.000 mol
Temperature (T)
273.1 K
Gas Constant (R)
0.08206 L·atm/(mol·K)

Step-by-Step Calculation

1. Ideal Gas Law

PV=nRTPV = nRT

2. Solve for Pressure

P=nRTVP = \frac{nRT}{V}P=(1.000)(0.08206)(273.1)22.41P = \frac{(1.000)(0.08206)(273.1)}{22.41}P=1.000 atmP = 1.000\text{ atm}

Reference Guide

The Ideal Gas Law

The ideal gas law relates pressure, volume, amount of gas, and temperature through a single equation.

PV=nRTPV = nRT

where R = 0.08206 L atm/(mol K) is the ideal gas constant.

STP Conditions

Standard Temperature and Pressure (STP) is 0 degrees C (273.15 K) and 1 atm. At STP, one mole of an ideal gas occupies 22.414 liters.

VSTP=22.414 L/molV_{\text{STP}} = 22.414 \text{ L/mol}

Unit Conversions

Always convert to consistent units before plugging into the formula. Common conversions include 1 atm = 101.325 kPa = 760 mmHg and degrees C = K minus 273.15.

Limitations

The ideal gas law works best at low pressures and high temperatures. Real gases deviate at high pressures or low temperatures, where intermolecular forces and molecular volume matter.