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Atomic Emission Lab

Explore how atoms emit light at specific wavelengths. Use the Rydberg equation to predict hydrogen spectral lines across the Lyman, Balmer, and Paschen series. Observe flame test colors for common elements and connect quantum energy levels to visible light.

Guided Experiment: Hydrogen Balmer Series Investigation

If electrons transition from higher energy levels (n=3 to n=7) down to n=2 in hydrogen, what wavelengths of light do you predict will be emitted? Will the lines be evenly spaced in the spectrum?

Write your hypothesis in the Lab Report panel, then click Next.

Controls

Upper Level (n₂)n₂ = 3 (transition 32)
n=3n=7

Emission Results

λ=656.3 nmE=1.889 eV\lambda = 656.3 \text{ nm} \quad E = 1.889 \text{ eV}
Wavelength
656.3 nm
Photon Energy
1.890 eV
Transition
n=3 → n=2
Color / Region
red
Energy Levels
E3E_{3}-1.511 eV
E2E_{2}-3.400 eV
ΔE\Delta E1.889 eV
Element: HydrogenBalmer series

Energy Level Diagram

Horizontal lines show hydrogen energy levels. Blue arrows show electron transitions for the selected series. Numbers are wavelengths in nm.

Data Table

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#TrialElementn (upper)n (lower)Wavelength(nm)Energy(eV)Color
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Reference Guide

Atomic Emission

When electrons in an atom fall from a higher energy level to a lower one, the energy difference is released as a photon of light. Each element has a unique set of energy levels, producing a characteristic emission spectrum — a fingerprint of bright lines.

For hydrogen, energy levels are given by:

En=13.6 eVn2E_n = -\frac{13.6 \text{ eV}}{n^2}

where n = 1, 2, 3, ... is the principal quantum number. The ground state (n=1) has the lowest energy at -13.6 eV.

Bohr Model

The Bohr model describes hydrogen as an electron orbiting a proton in fixed circular orbits. Each orbit corresponds to a quantum number n. Electrons absorb energy to jump to higher levels and emit photons when falling back.

The photon energy equals the energy level difference:

Ephoton=En2En1=hcλE_{\text{photon}} = E_{n_2} - E_{n_1} = \frac{hc}{\lambda}

where h = 6.626 × 10-34 J·s and c = 3 × 108 m/s.

Rydberg Equation

The Rydberg equation predicts the wavelengths of spectral lines in hydrogen:

1λ=RH(1n121n22)\frac{1}{\lambda} = R_H \left(\frac{1}{n_1^2} - \frac{1}{n_2^2}\right)

where RH = 1.097 × 107 m-1, n1 is the lower level, and n2 > n1 is the upper level.

  • Lyman series: n1 = 1 (UV)
  • Balmer series: n1 = 2 (visible)
  • Paschen series: n1 = 3 (IR)

Flame Tests

Flame tests identify elements by the color of light they emit when heated. Metal ions absorb heat energy, exciting electrons to higher levels. As electrons fall back, they emit photons at characteristic wavelengths.

Lithium (Li) — red
Sodium (Na) — yellow
Potassium (K) — violet
Calcium (Ca) — orange
Copper (Cu) — green
Strontium (Sr) — red